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prove that equation of parabola in standard form


939894113r 21st May, 2020
Answer (1)
Mounika Sonti 24th May, 2020

Hello!!!

Hope you are doing great!!!

Let 'S' be the focus and 'l' be the directrix of parabola

let 'Z' be the projection of 'S' on 'l' & A be the mid point of ZS such that AS=AZ=a

therefore A lies on the parabola

Let AY be parallel to 'l' & choose AY as Y-axis &AS as X-axis

A=(0,0) S(a,0) z(-a,0) and equation of directrix l=x=-a=x+a=0

Let p(x,y)be any point on the parabola

therefore SP/PM = 1 (by def)

=SP=PM

√ (x-a)^2 + y^2 = |x+a| / √ 1^2 + 0^2

Squaring on both sides

(x-a)^2 + y^2 = (x+a)^2

x^2-2ax + a^2 + y^2 = x^2 +a^2+2ax

therefore y^2= 4ax which is standard form of the parabola

Hope it helps!!!!!

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