Prove that sin theta minus cos theta + 1 by sin theta + cos theta minus 1 equal to 1 by sec theta minus tan theta
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Answer (1)
28th Dec, 2020
Hello there,
Let we take angle Thita as 'x' . We have to prove that Sinx - Cosx +1 / Sinx + Cosx - 1 = 1/ Secx - Tanx
So now we will take the LHS of the question.
Now multiply the numerator and denominator by Sinx + Cosx +1
Now, our left side becames 1+ Sinx / Cosx
Now again multiply the numerator and denominator by 1- Sinx
So we get , Cosx / 1 - Sinx.
Now just divide the numerator and denominator by Cosx .
Hence We get 1/ Secx - Tanx
Hope it helps you.
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Comments (4)
Thank u bro
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Can u pls provide a detailed answer by writing in a note book pls
28th Dec, 2020
Ysaswini
We can do so, but it is difficult to provide you the screenshot or image here, because we can't upload the image here. I have provided a detailed procedure to solve this problem. You just follow the steps and the answer will definitely came.
Parmeshwar Suhag
OK thank u
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