prove that (sin3x +sinx ) sinx+(cos3x-cosx) cosx =0
Answer (1)
2nd Jan, 2021
Dear Aspirant,
Kindly know all the formulas for trigonometry,
We know that,
sin A + sin B = 2*[sin(A+B)/2 * cos(A-B)/2]
& Similarly,
cos A - cos B = -2*[sin(A+B)/2 * sin(A-B)/2]
So using these formulas,
= (sin3x + sinx) * sinx + (cos3x - cosx) * cosx
= (2sin2xcosx) * sinx - (2sin2xsinx) * cosx
After multiplying the terms, you'll get 0 as the final result.
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