Q.28. A galvanic cell consists of a metallic zinc plate immersed in 0.1 MZn(NO3)2 Solution and metallic plate lead in 0.02 M Pb(NO3)solution. Write the chemical equation for the each electrode reaction, represent the cell and calculate EMF of the cell. (Ezn?*/zn. -0.76V; Eb**7 =-0.13V)
Answer (1)
3rd Feb, 2021
Hello candidate,
The formula for EMF of a cell in a Galvanic reaction is given by
EMF= E0- 0.059/n×{log Kc}. In this question, the value of E0= -0.13- (-.76)= 0.63 and the value of n=2. Kc equals to 0.2/0.1=2.
Hence putting all the values in the equation, we find the value of EMF = 0.63-.059/2×{log2} = 0.62 Volts.
Hope that this answer was helpful for you!!
Have a good day.
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