Correct Answer: INR 1,272

Solution : Given: Rahul invested equal sums of money at compound interest under two schemes A and B.
Under scheme A, the interest rate was 10% per annum, and under scheme B, the interest rate was 12% pa.
The compound interest after two years on the sum invested in scheme A was INR 1,050.
Use the formula, $A=P[1+\frac{R}{100}]^T$ where $A$, $P$, $R$ and $T$ are the amount, principal, rate, and number of years.
Let the sum be INR $P$.
The interest in scheme A is given as,
⇒ $2P(\frac{10}{100})+P(\frac{10}{100})^2=1050$
⇒ $\frac{2P}{10}+\frac{P}{100}=1050$
⇒ $\frac{20P+P}{100}=1050$
⇒ $21P=105000$
⇒ $P=$ INR 5,000
The interest in scheme B is given as,
= $2\times 5000 \times \frac{12}{100}+5000 \times (\frac{12}{100})^2$
= 1200 + 72
= INR 1,272
Hence, the correct answer is INR 1,272.