restiance of a wire is 3.1 ohm at 30 degree and 4.5 ohm at 100 Celsius temp then coefficient of resistivity is. ?
Answer (1)
Student Expert
29th Feb, 2020
Hello Jayesh
In the question, we have
R1 = 3.1 ohm at t = 300C
R2 = 4.5 ohm at t = 1000C
Also We have, R = R0 (1+t)
So, R1 = R0 (1+ * 30)
And,
R2 = R0 (1+ * 100)
Then,
R1 / R2 = [(1+30) / (1+100)]
3.1 /4.5 = [(1+30) / (1+100)]
Solving the above expression we get:
Temp. coefficient, = 0.0085 0C-1
Thankyou
In the question, we have
R1 = 3.1 ohm at t = 300C
R2 = 4.5 ohm at t = 1000C
Also We have, R = R0 (1+t)
So, R1 = R0 (1+ * 30)
And,
R2 = R0 (1+ * 100)
Then,
R1 / R2 = [(1+30) / (1+100)]
3.1 /4.5 = [(1+30) / (1+100)]
Solving the above expression we get:
Temp. coefficient, = 0.0085 0C-1
Thankyou
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