Question : Rs. 13000 is divided among X, Y, and Z such that 2 times X's share is equal to 3 times Y's share which is equal to 4 times Z's share. What is the share of Y?
Option 1: Rs. 3200
Option 2: Rs. 4800
Option 3: Rs. 5600
Option 4: Rs. 4000
New: SSC CHSL tier 1 answer key 2024 out | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: Rs. 4000
Solution : Let $2X = 3Y = 4Z = k$ $X =\frac{k}{2}, Y = \frac{k}{3}, Z = \frac{k}{4}$ The sum of shares of all of them together = 13000 ⇒ $\frac{k}{2} + \frac{k}{3} + \frac{k}{4} = 13000$ ⇒ $\frac{6k+4k+3k}{12}=13000$ ⇒ $\frac{13k}{12}=13000$ ⇒ $k = 12000$ $\therefore$ Share of $Y = \frac{1}{3}\times 12000=4000$ Hence, the correct answer is Rs. 4000.
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : An amount of Rs.12,029 is divided among P, Q, and R such that P's share is 5 times Q's share and R's share is one-third of P's share. what is the share of R?
Question : Simplify the given expression. $\frac{x^3+y^3+z^3-3 x y z}{(x-y)^2+(y-z)^2+(z-x)^2}$
Question : If $x$ = $y$ = $z$, then $\frac{\left (x+y+z \right )^{2}}{x^{2}+y^{2}+z^{2}}$ is equal to:
Question : If ${x^2+y^2+z^2=2(x+z-1)}$, then the value of $x^3+y^3+z^3$ is equal to:
Question : If $x+y+z=13$ and $x^2+y^2+z^2=69$, then $xy+z(x+y)$ is equal to:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile