Question : S and T are points on the sides PQ and PR, respectively, of $\triangle$PQR such that PS × PR = PQ × PT. If $\angle$Q = 96° and $\angle$PST = $\angle$PRQ + 34°, then $\angle$QPR = ?
Option 1: 24°
Option 2: 25°
Option 3: 22°
Option 4: 26°
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 22°
Solution : According to the question, PS × PR = PQ × PT ⇒ $\frac{PQ}{PS}$ = $\frac{PR}{PT}$ ⇒ ST || QR $\angle$ Q = $\angle$ PST = 96° (corresponding angles between two parallel lines) Since $\angle$ PST = $\angle$ PRQ + 34° ⇒ 96° = $\angle$ PRQ + 34° ⇒ $\angle$ PRQ = (96° – 34°) = 62° Now, ⇒ $\angle$ PQR + $\angle$ PRQ + $\angle$ QPR = 180° ⇒ 96° + 62° + $\angle$QPR = 180° ⇒ 158° + $\angle$QPR = 180° ⇒ $\angle$QPR = 180° – 158° ⇒ $\angle$QPR = 22° Hence, the correct answer is 22°.
Candidates can download this ebook to know all about SSC CGL.
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Question : In $\triangle {PQR} $, PQ = PR and S is a point on QR such that $\angle {PSQ}=96^{\circ}+\angle {QPS}$ and $\angle {QPR} = 132^{\circ}$. What is the measure of $\angle {PSR}$?
Question : A circle is inscribed in $\triangle $PQR touching the sides QR, PR and PQ at the points S, U and T, respectively. PQ = (QR + 5) cm, PQ = (PR + 2) cm. If the perimeter of $\triangle $PQR is 32 cm, then PR is equal to:
Question : In triangle PQR, the sides PQ and PR are produced to A and B respectively. The bisectors of $\angle {AQR}$ and $\angle {BRQ}$ intersect at point O. If $\angle {QOR} = 50^{\circ}$ what is the value of $\angle {QPR}$ ?
Question : In a $\triangle$PQR, the side QR is extended to S. If $\angle$QPR = 72° and $\angle$PRS=110°, then the value of $\angle$PQR is:
Question : In a triangle PQR, S, and T are the points on PQ and PR, respectively, such that ST || QR and $\frac{\text{PS}}{\text{SQ}} = \frac{3}{5}$ and PR = 6 cm. Then PT is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile