Hello Sourav,

According to the VESPR Theory , the shape of PCl5 is Trigonal Bipyramidal.

Here P is the central atom and it has 5 Cl atoms around it. The compound PCl5 has five electron pair around the central atom. It also has five bond pairs and no lone pair. It's hybridization is sp3d. Therefore it's shape is Trigonal Bipyramidal.

Hope this helps you.

Best of Luck!!

Hello Aspirant,

Talking about pcl5 , According to VEDPR theory , it is sp3d hybridized, having five 3sp3 d- 3p bonds .Now , total Valence electrons in pcl5 is = 7+5+5= 17. From the compound , it is clear that there are five (5) lone pairs of electron around p ( as 2+2+1 =5 electrons in valence shell so each cl atom having one lone pair). Hence the arrangement will be trigonal trigonal bipyramidal.


Hopes this helps.

Hello Student..

PCl5 has five electron pairs around central atom, five bond pairs no lone pairs. So the shape is trigonal bipyramidal.

PCl5: sp3d hybridization with five 3sp3 d-3p bonds in a triagonal bipyramid form.

In PCl5, the valence electrons are 5 + 5X7 = 40.

Around P, there are five lone pairs of electrons. As a result, these electrons will be arranged in a triagonal bipyramid around P. The hybridization involved in this complex is sp3d.

I hope this information helps .

Regards.