Question : Simplify: ${\frac{x^4-2 x^2+1}{x^2-2 x+1}}$
Option 1: $x^2-2 x+1$
Option 2: $x^2+2 x+2$
Option 3: $x^2+2 x+1$
Option 4: $x^2+x+1$
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: $x^2+2 x+1$
Solution : ${\frac{x^4-2 x^2+1}{x^2-2 x+1}}$ . $= \frac{(x^2-1)^2}{(x-1)^2}$ $=\frac{(x+1)^2(x-1)^2}{(x-1)^2}$ $= (x+1)^2$ $= x^2+2x + 1$ Hence, the correct answer is $ x^2+2x +1$.
Candidates can download this ebook to know all about SSC CGL.
Admit Card | Eligibility | Application | Selection Process | Preparation Tips | Result | Answer Key
Question : Simplify the following expression. $\frac{x^2-2 x-63}{x^2+14 x+49}$
Question : Simplify the following: $\frac{\cos x-\sqrt{3} \sin x}{2}$
Question : Simplify $\frac{1}{2 + 2 p} + \frac{1}{2 + 2 q} + \frac{1}{2 + 2 r}$, where $p = \frac{x}{y + z}$, if $q = \frac{y}{z + x}$ and $r = \frac{z}{x + y}$.
Question : The value of $(x^{\frac{1}{3}}+x^{-\frac{1}{3}})(x^{\frac{2}{3}}-1+x^{-\frac{2}{3}})$ is:
Question : Simplify: $\frac{256 x^4-16 y^4}{\left(80 x^2-20 y^2\right)\left(16 x^2+4 y^2\right)}$
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile