Question : Simplify the following expression. $(3x+5)^2+(3x-5)^2$
Option 1: $500x$
Option 2: $450x$
Option 3: $9x^2+50$
Option 4: $2\left(9 x^2+25\right)$
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: $2\left(9 x^2+25\right)$
Solution : Given: $(3x+5)^2+(3x-5)^2$ Expanding this expression by using algebraic identities, we have, $=[(3x)^2+(5)^2+2×3x×5]+[(3x)^2+(5)^2–2×3x×5]$ $= [9x^2+25+30x+[9x^2+25–30x]$ $= 18x^2+50$ $= 2(9x^2+25)$ Hence, the correct answer is $2(9x^2+25)$.
Candidates can download this ebook to know all about SSC CGL.
Admit Card | Eligibility | Application | Selection Process | Preparation Tips | Result | Answer Key
Question : Expand and simplify the algebraic expression: $(x-5)^2+(x+3)^2+4x$
Question : The factors of $ x^4+x^2+25$ are:
Question : Simplify the following equation. What is the difference between the two values of $x$? $7 x+4\left\{x^2 \div(5 x \div 10)\right\}-3\left\{5 \frac{1}{3}-x^3 \div\left(3 x^2 \div x\right)\right\}=0$
Question : If $x^{2} -3x +1=0$, then the value of $\frac{\left(x^4+\frac{1}{x^2}\right)}{\left(x^2+5 x+1\right)}$ is:
Question : Simplify the following: $\frac{\cos x-\sqrt{3} \sin x}{2}$
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile