13 Views
Question : Simplify the given expression $\frac{(x+3)^3+(x-3)^3}{x^2+27}$.
Option 1: $3x$
Option 2: $x$
Option 3: $4x$
Option 4: $2x$
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
Answer (1)
Correct Answer: $2x$
Solution :
Consider $\frac{(x+3)^3+(x-3)^3}{x^2+27}$
= $\frac{x^3+3^3+3\times x\times 3(x+3)+x^3-3^3-3\times x\times 3(x-3)}{}$
= $\frac{2x^3+9x(x+3)-9x(x-3)}{x^2+27}$
= $\frac{2x^3+9x^2+27x-9x^2+27x}{x^2+27}$
= $\frac{2x^3+2\times 27x}{x^2+27}$
= $\frac{2x(x^2+27)}{x^2+27}$
= $2x$
Hence, the correct answer is $2x$.
How to crack SSC CHSL
Candidates can download this e-book to give a boost to thier preparation.
Download NowKnow More About
Related Questions
TOEFL ® Registrations 2025
Apply
Accepted by 13,000 universities worldwide | Offered in 200+ countries | 40 million people have taken TOEFL Test
Upcoming Exams
Application Date:
28 May, 2025
- 17 Jun, 2025
Application Date:
28 May, 2025
- 17 Jun, 2025
Application Date:
5 Jun, 2025
- 26 Jun, 2025
1st Stage CBT
Exam Date:
5 Jun, 2025
- 24 Jun, 2025
Application Date:
23 Jun, 2025
- 18 Jul, 2025