Question : Simplify the given expression. (a – 2b)(b – 3a) + (a + b)(a – 3b) – (b – 3a)(4a – 5b)
Option 1: 8a2 – 10ab
Option 2: 8a2 + 10ab
Option 3: 10a2 – 14ab
Option 4: 10a2 – 4ab
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 10a 2 – 14ab
Solution : Given: (a – 2b)(b – 3a) + (a + b)(a – 3b) – (b – 3a)(4a – 5b) = (a – 2b)(–3a + b) + (a + b)(a – 3b) – (b – 3a)(4a – 5b) = –3a 2 + 6ab + ab – 2b 2 + a 2 + ab – 3ab – 3b 2 – (4ab –12a 2 – 5b 2 + 15ab) = –2a 2 + 5ab – 5b 2 – 19ab + 12a 2 + 5b 2 = 10a 2 – 14ab Hence, the correct answer is 10a 2 – 14ab.
Candidates can download this ebook to know all about SSC CGL.
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Question : Simplify the following expression. 2 + (30 – 26)2 ÷ 8{3 – 2} × 0.5
Question : What is the value of (a + b)3 – a3 + b3?
Question : Simplify the given expression. 15 – (–5) × {4 – (7 – 3)} ÷ [3 × {5 + (–3) × (–6)}]
Question : What is the value of a2 + b2 + c2 – 2ab – 2bc + 2ca?
Question : For what value of k will the expression x6 – 18x3 + k be a perfect square?
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile