Hello aspirant,
I will definitely help you.
The solution of above question is
Sin^-1 (√3/2√2 -1/2√2)
Sin^-1 (√3/2 *1/√2 -1/2 *1/√2)
Sin^-1 { (√3/2 *(√1-(1/√2)^2) -1/√2 * (√1-(√3/2)^2 }
Sin^-1 (√3/2) - Sin^-1 (1/√2)
π/3-π/4
π/12
Hope this helps you
Feel free to ask any questions
All the best for your future
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