Sir, I am getting marks of 134 in first sesson of JEE 2025. My exam was on 29 Jan (Second Shift). what is the expected percentile and rank.

Hello there,

With 134 marks in the JEE Main 2025 (29th Jan, Shift 2) , your expected percentile would be around 94-96%ile .

Expected Rank Calculation:

• The total number of candidates appearing for JEE Main is around 10-11 lakh .
• Using the formula:
  
  Rank = [(100 - Percentile) / 100] × Total Candidates

For 95 percentile , your expected rank would be around 50,000 - 55,000 .
If your percentile is 94 , your rank may go up to 60,000 - 65,000 .

Chances for NITs:

• NITs (Core branches like CSE, ECE, EE, ME, etc.) may be difficult in top NITs.
• You may get lower NITs or branches like Civil, Metallurgy, etc.
• If you belong to OBC/EWS/SC/ST , your chances improve significantly.
  
  
  
  I would recommend you to use JEE Mains College Predictor Tool by Careers360 to get the list of possible colleges you can get with your rank.
  
  
  I hope this answer helps you. If you have more queries then feel free to share your questions with us we will be happy to assist you.
  
  Thank you and wishing you all the best for your bright future.

Hello

Based on your JEE Main 2025 Session 1 score of 134 marks in the second shift on June 29, your estimated percentile and rank are as follows:

Expected Percentile :

Approximately between 94 to 96 percentile.

Expected Rank :

Approximately between 50,000 to 70,000.

These estimates are derived from previous years data and may vary depending on the exam's difficulty level and the performance of all candidates. For a more precise prediction, you can use the JEE Main Rank Predictor tools available online.

hope this helps you .