530 Views

Sir I got 96.1 percentile in jee paper 2 2019. How can I count my rank and which architecture colleges i should refer


Bhavya Ghevariya 1st Feb, 2019
Answers (2)
Manikarnika 1st Feb, 2019

Hi Bhavya,

This year a total of 1,45,386 aspirant appeared for the JEE B.Arch Examination. Therefore, basing upon the total number of aspirants the formula for calculating your rank would be ([100-your percentile] x 145386)/100. Therefore, approximately your rank will be around 5,670.

Considering your rank of 5,670, you can geta admission to various colleges. However, you can check for yourself depending upon your category and the state you belong to. Use last year's cut off, opening and closingrank, to predict a colleg for yourself. (Link is here: https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning#) It surely varies but not majorly.


To clear any doubts or to know more about JEE B.Arch Results, keep reading Careers 360 using the link given below: Https://engineering.careers360.com/articles/jee-main-paper-2-result

Thanks,

Sanket Sanglikar 1st Feb, 2019


Hello Bhavya

Congrats for scoring 96.1 percentile in JEE main paper 2.

We can't say that which NIT you wil get but we can predict the rank with this percentile .

There is a pedicted formula from our team to predict rank

Total No of students = 145386

Formula

Probable Rank= ( 100 - your NTA percentile ) x 145386 / 100

So your predicted rank  = 5670 approx

Our Team predicted that the qualify cutt off would be above 85 percentile .But it just a prediction .So pleae wait till april.


You have  scored very  good percentile so according to me you will get admission  in following NIT's...

  • National Institute of Technology, Tiruchirapalli, Tamilnadu
  • National Institute of Technology, Warangal, Andhra Pradesh
  • National Institute of Technology, Surathkal, Karnataka
  • Moulana Azad National Institute of Technology, Bhopal, M.P
  • Motilal Nehru National Institute of Technology, Allahabad, U.P
  • National Institute of Technology, Calicut, Kozhikode, Kerala
  • National Institute of Technology, Durgapur, West Bengal
  • National Institute of Technology, Hamirpur, Himachal Pradesh
  • Malaviya National Institute of Technology, Jaipur, Rajasthan
  • Dr. B R Ambedkar National Institute of Technology, Jalandhar, Punjab


I hope you get my point.

Good Luck!!!

1 Comment
Comments (1)
10th May, 2019
Is this true?  Is MNIT BHOPAL AND JAIPUR available at 96.1 percentile? 
Reply
JEE Main Exam's High Scoring Chapters and Topics

This free eBook covers JEE Main important chapters & topics to study just 40% of the syllabus and score up to 100% marks in the examination.

Download EBook

Know More About

Related Questions

UPES B.Tech Admissions 2025
Apply
Ranked #42 among Engineering colleges in India by NIRF | Highest CTC 50 LPA , 100% Placements
Dayananda Sagar University B....
Apply
60+ Years of Education Legacy | UGC & AICTE Approved | Prestigious Scholarship Worth 6 Crores | H-CTC 35 LPA
Parul University B.Tech Admis...
Apply
India's youngest NAAC A++ accredited University | NIRF rank band 151-200 | 2200 Recruiters | 45.98 Lakhs Highest Package
Lovely Professional Universit...
Apply
India's Largest University | NAAC A++ Accredited | 100% Placement Record | Highest Package Offered : 3 Cr PA
Atlas SkillTech University | ...
Apply
Hands on Mentoring and Code Coaching | Cutting Edge Curriculum with Real World Application
Pearson | PTE
Apply
Register now for PTE & Unlock 20% OFF : Use promo code: 'C360SPL20'. Valid till 30th NOV'24! Trusted by 3,500+ universities globally
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books