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Sir. My percentile score in Jee mains 2019 is80.77. I m in General catagory Is this a good score to qualify for advance? My rank would-be


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AMRUT 19th Jan, 2019
Answer (1)
manisha.gupta 19th Jan, 2019

It is difficult to predict the actual rank or JEE Advance qualifying marks as first time JEE is being conducted twice and rank will be based on NTA percentile score but you may calculate  your expected rank by given below Formula.

874469 are the number of candidates appeared for the January exam. So rank formula is (100- your total score) * 874469 / 100.

If the number of candidates for April exam increased to 1400000 then your final rank shall be (100- your total score) * 1400000/100.

Good Luck!

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7 Comments
Comments (7)
19th Jan, 2019
Wat formula is this. Kindly give rcexamp
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20th Jan, 2019
Total score means percentile or marks
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21st Jan, 2019
To calculate your rank, The formula would be 100 which is the highest score minus (-) your percentile score.The percentile is calculated from a scale ranging from 100 to 0 for each session of examinees, The formula applies the total number of students in the January session which is 874469 /100 multiplied by the percentage of people who are a head of you to arrive at the rank.For Example- If NTA percentile score is 80.60, JEE Main rank will be (100-80.60 ) X 874469/100 = 169646.This formula would not be for a 100 percentile score as those are the top ranks.
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30th Apr, 2019
Where can I get admission if I have got 80 percentile in JEE mains and I belong to gen category??
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1st May, 2019
@ Shreya Dubey- Kindly share your Overall Rank, I can help you better about the admission possibilities.
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12th May, 2019
Sir I got 80 percentile and 70500 rank in obc  shall i get any nit for cse please clarify my doubt
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13th May, 2019
@Srinivasarao Gedela- With this rank the chances are less to get a seat in NITs, IIITs, GFTIs however you can check your admission possibilities in state level counselling with JEE Main College Predictor tool.https://engineering.careers360.com/jee-main-college-predictor
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