Given, (x+y)/xy = 2 => (x+y)=2xy----(i)

(x-y)/xy = 6 => x-y=6xy-----(ii)

Adding equation (i) & (ii),

x+y+x-y = 2xy+6xy = 8xy

=> 2x=8xy => y=1/4

Putting the value of y in eqn (i) we get,

x+1/4=2x*(1/4) => x+1/4=x/2=> x/2=-1/4 => x=-1/2

SO by solving both the equations we get, x=-1/2, y=1/4

Here, *= Multiplication

I hope my answer helps. All the very best for your future endeavors!