Question : Study the pie chart and answer the options:
The total number of students specializing in A and B exceeds the total number of students specializing in C and D by x, which lies between:
Option 1: 60 and 65
Option 2: 55 and 60
Option 3: 50 and 55
Option 4: 65 and 70
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Correct Answer: 60 and 65
Solution :
Total number of students specializing in A and B = $(61.2^\circ + 75.6^\circ) = 136.8^\circ$
Total number of students specializing in C and D = $(72^\circ + 54^\circ) = 126^\circ$
Difference of A and B and C and D = $(136.8^\circ – 126^\circ) = 10.8^\circ$
Given $360^\circ = 2100$
⇒ $1^\circ = \frac{2100}{360}$
⇒ $10.8^\circ = \frac{2100}{360} × 10.8^\circ$
= $\frac{2268}{36}$
= $63$
Hence, the correct answer is 60 and 65.
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