Question : Suhas, a tree, and an 11.25 m tall building are positioned such that their feet on the ground are collinear and the tree is located between Suhas and the building. The tree is located at a distance of 7.5 m from Suhas and a distance of 45 m from the building. Further, the eyes of Suhas, the top of the tree, and the top of the building fall in one line, and the eyes of Suhas are at a height of 1.8 m from the ground. Find the height (in m ) of the tree.
Option 1: 3.00 m
Option 2: 3.30 m
Option 3: 3.15 m
Option 4: 3.45 m
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Correct Answer: 3.15 m
Solution : Given: All points are collinear. Height of Suhas be $a$ = 1.8 m Height of building be $b$ = 11.25 m Let the height of the tree be $c$ Distance between Suhas and tree be $x$ = 7.5 m Distance between tree and building be $y$ = 45 m The ratio of the distance between Suhas and tree : tree and building = 7.5 : 45 = 1 : 6 Sum = 1 + 6 = 7 $c$ = $\frac{ay+bx}{x+y}$ = $\frac{(1.8×6)+(11.25×1)}{x+y}$ = $\frac{10.8+11.25}{7}$ = $\frac{22.05}{7}$ = $3.15$ Hence, the correct answer is 3.15 m.
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Question : Suhas, a 3.15 m tall tree, and a building are positioned such that their feet on the ground are collinear and the tree is located between Suhas and the building. The tree is located at a distance of 7.5 m from Suhas and a distance of 45 m from the building. Further, the eyes
Question : Suhas, a 3.15 m tall tree, and an 11.25 m tall building are positioned such that their feet on the ground are collinear and the tree is located between Suhas and the building. The tree is located at a distance of 45 m from the building. Further. the eyes of Suhas, the top of
Question : Subhas, a 3.15 m tall tree, and an 11.25 m tall building are positioned such that their feet on the ground are collinear and the tree is located between Subhas and the building. The tree is located at a distance of 7.5 m from Subhas and a distance of 45 m from the building.
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