Question : Sum of the factors of $4b^2c^2-(b^2+c^2-a^2)^2$ is:
Option 1: $a+b+c$
Option 2: $2(a+b+c)$
Option 3: $0$
Option 4: $1$
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: $2(a+b+c)$
Solution : $4b^2c^2-(b^2+c^2-a^2)^2$ $=(2bc)^2-(b^2+c^2-a^2)^2$ $=(2bc+b^2+c^2-a^2)(2bc-b^2-c^2+a^2)$ $=((b + c)^2-a^2)(a^2-(b^2+ c^2-2bc))$ $=(b + c + a) (b + c -a) (a^2 -(b-c)^2)$ $=(b+ c+a) (b + c -a) (a + b -c) (a -b + c)$ So, the required sum of factors is given as $b+c+a+b+c-a+a+b-c+a-b+ c=2(a+b+c)$ Hence, the correct answer is $2(a+b+c)$.
Candidates can download this ebook to know all about SSC CGL.
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Question : The mean proportional of $a$ and $b$ is $c$. What is the mean proportion of $a^2c$ and $b^2c$?
Question : If $x+\frac{1}{x}=c+\frac{1}{c}$, then the value of $x$ is:
Question : If $a+b=2c$, then the value of $\frac{a}{a–c}+\frac{c}{b–c}$ is equal to (where $a\neq b\neq c$):
Question : The value of $x$ which satisfies the equation $\frac{x \:+\: a^2 \:+\: 2c^2}{b \:+\: c} + \frac{x \:+\: b^2 \:+\: 2a^2}{c+a} + \frac{x \:+\: c^2 \:+\: 2b^2}{a \:+\: b} = 0$ is:
Question : What is the value of ${a}^3+{b}^3+{c}^3$ if $(a+b+c)=0$?
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile