So, this is a question from the topic Permutation and Combination.

So basically you have digits 2, 2, 3, 3. Now, using these, you wish to know the number of four digit numbers which can be formed.

No. of 4 digit Numbers = 4!/(2!2!) which is equal to 6.

And these 6 numbers are as follows:

2233, 3322, 2323, 3232, 3223, 2332

The greatest one is 3322 while the smallest one is 2233.

In Total, 6 different numbers can be formed.

Hope this helps.