take two digits two and three make four digit number using both the digits equal number of time.
Answer (1)
10th Jul, 2020
So, this is a question from the topic Permutation and Combination.
So basically you have digits 2, 2, 3, 3. Now, using these, you wish to know the number of four digit numbers which can be formed.
No. of 4 digit Numbers = 4!/(2!2!) which is equal to 6.
And these 6 numbers are as follows:
2233
3322
2323
3232
3223
2332
Hope this helps.
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