The acceleration potential for a x-ray machine is 50000 volts. The shortest wavelength present in the radiation is
Hey,
We can determine the minimum wavelength of emitted x-rays, using the following formula:
λ m i n = h c / e V λmin=hc/eV
Where h is Planck’s constant, c is speed of light and eV the applied potential (for this purpose, the same as KV).
So, in your case it would be:
λ m i n = 1.23984193 / 50 = 0.0247968386 p m
