Question : The altitude of an equilateral triangle of side $\frac{2}{\sqrt3}$ cm is:
Option 1: $\frac{4}{3}$ cm
Option 2: $\frac{4}{\sqrt3}$ cm
Option 3: $\frac{2}{3}$ cm
Option 4: $1$ cm
Correct Answer: $1$ cm
Solution : Given: Side of equilateral triangle = $\frac{2}{\sqrt3}$ m Altitude of an equilateral triangle of side $a$ = $\frac{\sqrt3}{2}a$ $\therefore$ The altitude of the triangle is $\frac{\sqrt3}{2}×\frac{2}{\sqrt3}$ = 1 cm Hence, the correct answer is $1$ cm.
Result | Eligibility | Application | Selection Process | Cutoff | Admit Card | Preparation Tips
Question : If the area of an equilateral triangle is $a$ and height $b$, then the value of $\frac{b^2}{a}$ is:
Question : ABCD is a square. Draw an equilateral $\triangle $PBC on side BC considering BC is a base and an equilateral $\triangle $QAC on diagonal AC considering AC is a base. Find the value of $\frac{\text{area of $\triangle PBC$}}{\text{area of $\triangle QAC$}}$.
Question : The area of an equilateral triangle is $4 \sqrt{3} \mathrm{~cm}^2$. Find the side (in cm) of the triangle.
Question : If each side of an equilateral triangle is 12 cm, then its altitude is equal to:
Question : The length of each side of an equilateral triangle is $14 \sqrt{3}$ cm. The area of the incircle (in cm2), is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile