the angle of prism is A .one of its refraction surface is silvered . light Ray falling angle 2A on the first surface return back through same path after reflection surface refractive index ?
Hello aspirant
To retrace its path light rays should fall normally on the reflecting surface. So,
r2=0
r1=A−r2⇒r1=A
Now applying snell rule between incident ray and refracted ray.
(1) sin (2A) = n sin A
2sinAcosA=nsinA
Therefore, n=2cosA
I.e The refractive index μ, of the prism is 2cosA.
Hope this helps