Question : The angles of elevation of a pole from two points which are 75 m and 48 m away from its base are $\alpha$ and $\beta$, respectively. If $\alpha$ and $\beta$ are complementary, then the height of the tower is:
Option 1: 54.5 m
Option 2: 61.5 m
Option 3: 60 m
Option 4: 50 m
Correct Answer: 60 m
Solution : Given, BD = 48 and BC = 75 In △ABD, $\tan β = \frac{AB}{BD}$ ⇒ $\tan β = \frac{AB}{48}$ ⇒ $AB = 48 \tan β$ ...........(1) In △ABC, $\tan α = \frac{AB}{BC}$ ⇒ $AB = 75 \tan α$ .............(2) Multiply by equation (1) from equation (2), ⇒ $AB^2 = 48 × 75 × \tan α × \tan β$ As we know, $α + β = 90°$ ⇒ $\tan α \tan β = 1$ ⇒ $AB = \sqrt{48 × 75}$ ⇒ $AB = \sqrt{16 × 3 × 3 × 25}$ ⇒ AB = 4 × 3 × 5 = 60 m Hence, the correct answer is 60 m.
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