Question : The angles of elevation of the top of a tower from two points on the ground at distances 32 m and 18 m from its base and in the same straight line with it are complementary. The height (in m) of the tower is____________.
Option 1: 20
Option 2: 24
Option 3: 16
Option 4: 28
Correct Answer: 24
Solution :
Given :
BD = 32 m
BC = 18 cm
Since $\angle$ADB and $\angle$ACB are complimentary.
So,
Height of the tower $AB = \sqrt{BD×BC}=\sqrt{32\ \times\ 18 } = 24$
Hence, the correct answer is 24.
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