Question : The area of an equilateral triangle is $4 \sqrt{3} \mathrm{~cm}^2$. Find the side (in cm) of the triangle.
Option 1: $2$
Option 2: $4$
Option 3: $\sqrt{3}$
Option 4: $2 \sqrt{3}$
Correct Answer: $4$
Solution : It is known that the area of the equilateral triangle = $\frac{\sqrt{3}}{4}a^2$ Where $a$ is the side of the equilateral triangle. It is given that the area of the equilateral triangle is $4\sqrt{3}$ cm$^2$ So, $\frac{\sqrt{3}}{4}a^2$ = $4\sqrt{3}$ ⇒ $a^2 = 16$ ⇒ $a = 4$ cm Hence, the correct answer is 4. .
Result | Eligibility | Application | Selection Process | Cutoff | Admit Card | Preparation Tips
Question : Find the area of triangle whose sides are 10 cm, 12 cm, and 18 cm.
Question : Find the area of a triangle whose length of two sides are 4 cm and 5 cm and the angle between them is 45°.
Question : If each side of an equilateral triangle is 12 cm, then its altitude is equal to:
Question : The length of each side of an equilateral triangle is $14 \sqrt{3}$ cm. The area of the incircle (in cm2), is:
Question : In a triangle ABC, if $\angle B=90^{\circ}, \angle C=45^{\circ}$ and AC = 4 cm, then the value of BC is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile