Question : The average of 16 numbers is 35. It was found later that four numbers 18, 17, 24, and 35 were taken by mistake. What is the new average after removing these numbers?
Option 1: 38.83
Option 2: 42.33
Option 3: 46.66
Option 4: 33.33
New: SSC CHSL Tier 2 answer key released | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 38.83
Solution : Given that the average of 16 numbers is 35, we can calculate the sum of those 16 numbers as follows: Sum = Average × Count ⇒ Sum = 35 × 16 = 560 So, Adjusted Sum = Sum – Sum of Mistaken Numbers ⇒ Adjusted Sum = 560 – (18 + 17 + 24 + 35) = 466 Since we removed four numbers, the count of the remaining numbers is 16 – 4 = 12. The new average is then calculated by dividing the adjusted sum by the new count, New average =$\frac{\text{ Adjusted Sum}}{\text{New Count}} = \frac{466}{12}$ = 38.83 (rounded to two decimal places) Hence, the correct answer is 38.83.
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : The average of 30 numbers is 40 and that of the other 40 numbers is 30. The average of all the numbers is:
Question : The average of 100 observations was calculated as 35. It was found later, that one of the observations was misread as 83 instead of 53. The correct average is:
Question : The average of 6 consecutive even numbers is 35. What will be the sum of the smallest and largest even number among these 6 numbers?
Question : The average of 8 numbers is 21. If each of the numbers is multiplied by 8, the average of the new set of numbers is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile