Question : The average of five consecutive positive integers is n. If the next two integers are also included, the average of all these integers will:
Option 1: increase by 1.5
Option 2: increase by 1
Option 3: remain the same
Option 4: increase by 2
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: increase by 1
Solution : Let $(x–2),(x–1), x, (x+1), (x+2)$ be the 5 consecutive positive integers. The average of an AP with an odd number of terms = middle term $⇒ x = n$ When the next two integers are also included, $⇒ (x–2),(x–1), x, (x+1), (x+2), (x+3), (x+4)$ New average = middle term $= (x+1) = n+1$ ⇒ Average has increased by 1. Hence, the correct answer is 1.
Candidates can download this ebook to know all about SSC CGL.
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Question : The average of 5 consecutive integers starting with 'm' is n. What is the average of 6 consecutive integers starting with (m + 2)?
Question : The average of three consecutive even numbers is A. If the next five even numbers are added, what is the average of these eight numbers?
Question : The average of $n$ numbers is $a$. The first number is increased by 2, the second one is increased by 4, the third one is increased by 8, and so on. The average of the new numbers is:
Question : If $m$ and $n$ are two positive real numbers such that $9 m^2+n^2=40$ and $mn = 4$, then the value of $3m + n$ is:
Question : The average of two numbers is 8, and the average of the other three numbers is 3. The average of the five numbers is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile