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The average of n number is 32. If three fourth of the number are increased by 4 and the remaining are decreased by 6, what is the new average?


Simran Sharma 17th Dec, 2019
Answer (1)
Ameya Narendra Parkar 17th Dec, 2019
Dear simran,
Let me help you to solve this question
  • The sum of the original n number is 32n
  • If 3/4th of the numbers are each increased by 4 their sum and therefore the sum of n increases by 3/4n X 4=3n
  • If 1/4th each decreased by 6 their sum and therefore the sum of all n number decreases by 1/4n X 6=3n/2
  • New sum is 32n + 3n - 3n/2 = 67n/2
  • New average is 33.5

I hope you understand this answer

all the best

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