The average of n number is 32. If three fourth of the number are increased by 4 and the remaining are decreased by 6, what is the new average?
Answer (1)
17th Dec, 2019
Dear simran,
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Let me help you to solve this question
- The sum of the original n number is 32n
- If 3/4th of the numbers are each increased by 4 their sum and therefore the sum of n increases by 3/4n X 4=3n
- If 1/4th each decreased by 6 their sum and therefore the sum of all n number decreases by 1/4n X 6=3n/2
- New sum is 32n + 3n - 3n/2 = 67n/2
- New average is 33.5
I hope you understand this answer
all the best
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