Question : The average of nine consecutive numbers is $n$, if the next two numbers are also included the new average will be:
Option 1: increase by 2
Option 2: remain the same
Option 3: increase by 1.5
Option 4: increase by 1
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Correct Answer: increase by 1
Solution : Given: The average of nine consecutive numbers is $n$. So, fifth number = $n$ Tenth number = $n + 5$ Eleventh number = $n + 6$ $\therefore$ New average = $\frac{9n + n + 5 + n + 6}{11}=\frac{(11n+11)}{11} = \frac{(n+1)\times 11}{11} = (n+1)$ Hence, the correct answer is "increases by 1".
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