Question : The average of three consecutive odd numbers is 52 more than $\frac{1}{3}$rd of the largest number. What is the smallest of these numbers?
Option 1: 79
Option 2: 75
Option 3: 81
Option 4: 77
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 77
Solution : Let $(x–2), x$ and $(x+2)$ be the 3 consecutive odd numbers. Average of AP with an odd number of terms = middle term ⇒ Average = $x$ Since the average of 3 consecutive odd numbers is 52 more than $\frac{1}{3}$rd of the largest number, $x = 52+\frac{(x+2)}{3}$ ⇒ $3x = (52×3)+(x+2)$ ⇒ $2x = 158$ ⇒ $x = 79$ Smallest number = 79 – 2 = 77 Hence, the correct answer is 77.
Candidates can download this ebook to know all about SSC CGL.
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Question : The sum of three consecutive even numbers is 28 more than the average of these three numbers. Then the smallest of these three numbers is:
Question : The average of seven consecutive numbers is 20. The largest of these numbers is:
Question : The sum of three fractions is $2\frac{11}{24}$. On dividing the largest faction by the smallest fraction, $\frac{7}{6}$ is obtained which is $\frac{1}{3}$ greater than the middle fraction. The smallest fraction is:
Question : The average of four consecutive odd numbers is 40. What is the largest number?
Question : The average of three consecutive even numbers is A. If the next five even numbers are added, what is the average of these eight numbers?
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile