Question : The bar graph given here shows the data on the production of cars by three different companies X, Y, and Z over the years. The average production for 5 years was the maximum for which company/companies?
Option 1: Y and Z
Option 2: Y
Option 3: X and Y
Option 4: X and Z
Correct Answer: X and Z
Solution : According to the question, Total production of company X over 5 years = 30 + 45 + 25 + 50 + 40 = 190 Average production over 5 years = $\frac{190}{5}$ = 38 cars Total production of company Y over 5 years = 25 + 35 + 35 + 40 + 50 = 185 Average production over 5 years = $\frac{185}{5}$ = 37 cars Total production of company Z over 5 years = 35 + 40 + 45 + 35 + 35 = 190 Average production over 5 years = $\frac{190}{5}$ = 38 cars ∴ The average production for 5 years was the maximum for X and Z companies. Hence, the correct answer is X and Z.
Result | Eligibility | Application | Selection Process | Cutoff | Admit Card | Preparation Tips
Question : The bar graph given here shows the data on the production of cars by three different companies X, Y, and Z over the years. For which of the
Question : The given bar graph shows the number of students of two schools over six years.
In the bar graph, in which year is the sum of the students from
Question : Study the given bar graph and answer the following question. The bar graph shows the number of employees recruited (in lakhs) by three different companies in five different years.
Question : What is $\frac{\left (x^{2}-y^{2} \right)^{3}+\left (y^{2}-z^{2} \right )^{3}+\left (z^{2}-x^{2} \right )^{3}}{\left (x-y \right)^{3}+\left (y-z \right )^{3}+\left (z-x \right)^{3}}?$
Question : If $x+y+z=19, x y z=216$ and $x y+y z+z x=114$, then the value of $x^3+y^3+z^3+x y z$ is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile