Question : The batting average for 27 innings of a cricket player is 47 runs. His highest score in an innings exceeds his lowest score by 157 runs. If these two innings are excluded, the average score of the remaining 25 innings is 42 runs. Find his highest score in an innings.
Option 1: 176
Option 2: 188
Option 3: 186
Option 4: 174
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Correct Answer: 188
Solution :
Given: The batting average for 27 innings of a cricket player is 47 runs.
The batting average for 25 innings is 42 runs (High and low scores excluded).
Also, His highest score (H) in an innings exceeds his lowest score (L) by 157 runs.
⇒ H – L = 157
Now, for total runs in those two innings,
(H + L) = (47 × 27) – (42 × 25)
⇒ (H + L) = 219 runs
Adding the two equations, we get,
So, 2H = 219 + 157 = 376
$\therefore$ H = 188 runs
Hence, the correct answer is 188.
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