Question : The circumference of the base of a cylinder is $28 \pi$ cm. If the height of the cylinder is 17 cm, then what will be the curved surface area of the cylinder?
Option 1: $372 \pi ~\text{cm}^2$
Option 2: $436\pi \ \text{cm}^2$
Option 3: $524\pi \ \text{cm}^2$
Option 4: $476\pi \ \text{cm}^2$
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Correct Answer: $476\pi \ \text{cm}^2$
Solution : Given: The circumference of the base of the cylinder = $28 \pi ~\mathrm{cm}$ We know that, Circumference of a circle = $2 \pi r$ ⇒ $2 \pi r = 28 \pi$ ⇒ $r = \frac{28 \pi}{2 \pi} = 14~\mathrm{cm}$ Height of the cylinder = 17 cm $\therefore$ Curved surface area of the cylinder = $2 \pi r h=2 \times\pi \times 14 \times 17=476\pi~\mathrm{cm}^2$ Hence, the correct answer is $476\pi \ \text{cm}^2$.
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