Question : The current population of the town is 68,000. The population increases by 10 percent in the first year and decreases by 30% in the second year. Find the population after 2 years.
Option 1: 52,360
Option 2: 68,500
Option 3: 69,000
Option 4: 70,100
New: SSC MTS 2024 Application Form OUT; Direct Link
Don't Miss: Month-wise Current Affairs | Upcoming Government Exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 52,360
Solution : Given: The current population of the town is 68,000. Percentage = $\frac{\text{Value}}{\text{Total value}}\times 100$ The population increases by 10% in the first year, then the population becomes = 68000 + $\frac{10}{100}\times 68000$ = 68000 + 6800 = 74,800 The population decreases by 30% in the second year = 74800 – $\frac{30}{100}\times 74800$ = 74800 – 22440 = 52,360 Hence, the correct answer is 52,360.
Application | Cutoff | Selection Process | Preparation Tips | Eligibility | Exam Pattern | Admit Card
Question : The population of a town increases by 8% every year. If the present population of the town is 14,580, then what was the population of the town 2 years ago?
Question : If the population of a town is 12,000 and the population increases at the rate of 10% per annum, then find the population after 3 years.
Question : The population of a town increases at the rate of 20% per annum. If the town's population will be 69,120 after 2 years, then what is the town's present population?
Question : The value of a machine is 6,250. It decreases by 10% during the first year, 20% during the second year and 30% during the third year. What will be the value of the machine after 3 years?
Question : Negative feedback in amplifiers
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile