the current through two inductor L1 and l2 is increasing with time at the same rate . draw a graph showing the variation of the end induced with the rate of change of current in each inductor
Hello,
In this case two situtations are possible where the value of L1<L2 or L1>L2.
Assuming L1<L2-
1)Calculate e1 = -L1(di/dt)
2)Similarly e2 = -L2(di/dt)
So now for drawing graph take the x axis as (di/dt) thats is rate of change of current and the y axiz as emf(e).As the value of the above calculated emf is resulting as negative,the straight line will be drawn in the fourth quadrant or the area of negative y axis and positive x axis.
As L2>L1 the slope of e2 will be greater so first draw a straight line for e2 strating from 0(origin) in the negative y region(4th quadrant) but L1 is smaller than L2 hence the slope of line e1 will be smaller than e2 hence we draw a straight line for e1 above e2 starting from the origin(0) towards the negative y region.
But if L1>L2 as in case 2 we will line for e1 below the line e2 in the fourth quadrant as slope of e1 is greater than e2 with both lines starting from the origin.(0,0)
Hope this helps!
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