8 Views

Question : The diagonal of the square is $8 \sqrt{2}$ cm. Find the diagonal of another square whose area is triple that of the first square.

Option 1: $8 \sqrt{5}$ cm

Option 2: $8 \sqrt{3}$ cm

Option 3: $8 \sqrt{2}$ cm

Option 4: $8 \sqrt{6}$ cm


Team Careers360 24th Jan, 2024
Answer (1)
Team Careers360 25th Jan, 2024

Correct Answer: $8 \sqrt{6}$ cm


Solution : Given, Diagonal = $8\sqrt2$
$\therefore$ Side = $\frac{8\sqrt{2}}{\sqrt 2}=8$ cm
⇒ Area of this square = $(8)^2 = 64$ cm 2
The Area of the Second square is triple the first one.
⇒ Area of the second one $= 64×3$
$\therefore$ Side of the 2nd square $= \sqrt{64×3} = 8\sqrt3$
⇒ The diagonal 2nd square $= \sqrt2×8\sqrt3 = 8\sqrt{6}$ cm
Hence, the correct answer is $8\sqrt6$ cm.

SSC CGL Complete Guide

Candidates can download this ebook to know all about SSC CGL.

Download EBook

Know More About

Related Questions

TOEFL ® Registrations 2024
Apply
Accepted by more than 11,000 universities in over 150 countries worldwide
Manipal Online M.Com Admissions
Apply
Apply for Online M.Com from Manipal University
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books