Question : The distance between P and Q is 720 km. A train leaves P at 6 am and runs at a speed of 20 m/s. The train stops on the way for 1 hour 30 minutes. At what time the train will reach at Q?
Option 1: 5:00 PM
Option 2: 4:45 PM
Option 3: 5:15 PM
Option 4: 5:30 PM
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Correct Answer: 5:30 PM
Solution :
Given: Distance = 720 km
Speed = 20 m/s = $20\times\frac{18}{5}$ = $72$ km/hr
Starting time = 6:00 am
Stoppage = 1 hour 30 minutes or 1.5 hours
We know that,
Speed = $\frac{\text{Distance}}{\text{Time}}$
⇒ $72 = \frac{720}{\text{Time}}$
⇒ Time = 10 hours
Including stoppage = 10 + 1.5 hours = 11.5 hours
The train will arrive at 6:00 AM + 11.5 hours = 5:30 PM
Hence, the correct answer is 5:30 PM.
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