Question : The distance between places A and B is 999 km. An express train leaves place A at 6 am and runs at a speed of 55.5 km/h. The train stops on the way for 1 hour 20 minutes. It reaches B at:
Option 1: 1:20 am
Option 2: 12 pm
Option 3: 6 pm
Option 4: 11 pm
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
Correct Answer: 1:20 am
Solution :
The speed of the express train is 55.5 km/h.
The distance is 999 km.
We know the formula Time = $\frac{\text{Distance}}{\text{Speed}}$.
⇒ Required time = $\frac{999}{55.5}$ = 18 hours.
So, the train will reach B at (6 am + 18 hours + 1 hour 20 minutes) = 1:20 a.m.
Hence, the correct answer is 1:20 am.
Related Questions
Know More about
Staff Selection Commission Combined Grad ...
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Get Updates Brochure
Your Staff Selection Commission Combined Graduate Level Exam brochure has been successfully mailed to your registered email id “”.
