the distance by which stone falls under gravity is directly proportional to square of time of fall. if a stone falls by 78 m in the 7th sec find the total distance it would fall in 1st 4sec
Answer (1)
5th Jan, 2020
Hello,
Given that the distance is directly proportional to the square of time.
So, d ∝ t^2
So, d = k.t^2
Where, k is the constant of proportionality.
Now from first condition,
d = 78m and t = 7 sec.
So, 78 = k. 7^2
So, k = 1.59 = 1.6
Now, d = k. t^2
So, for first four seconds, t = 4sec
So, d = k. 4^2
So, d = 1.6 x 16
So, d = 25.6 m
So, The stone will fall a total distance of 25.6 m in 1st 4 seconds.
Best Wishes.
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