N2(g) + 3H2(g) ------> 2NH3(g) ; rH° = -92.4 KJ/mol
enthalpy of formation of NH3 means heat released in the formation of 1 mole of NH3 .
so, divide both sides by 2 in above reaction
1/2N2(g) + 3/2H2(g) ---> NH3(g) ;
Therefore , fH° = rH°/2 = -92.4/2 = 46.2 KJ/mol
Thank you.
Question : The first law of thermodynamics is simply the case of:
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