the equation of a straight line perpendicular to 3x-4y=6 and forming a triangle of a area 6q.units with coordinate axes?
Answer (1)
10th Jun, 2018
Hello dear,
i have given below solution.
given equation is 3x-4y=6
we rewrite the equation , 4y=3x-6
y=(3/4)x-3/2
in these equation,slope=3/4
the coordinating point here is (o,-3/2)
set y=0 then ,0=(3/4)x-3/2
3/4x=3/2
x=2
here the coordinating point is (2,0)
Hope This Helps.
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