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the equation of a straight line perpendicular to 3x-4y=6 and forming a triangle of a area 6q.units with coordinate axes?


sai prasanna 1st May, 2018
Answer (1)


Hello dear,

i have given below solution.

given equation is 3x-4y=6

we rewrite the equation , 4y=3x-6

y=(3/4)x-3/2

in these equation,slope=3/4

the coordinating point here is  (o,-3/2)

set y=0 then  ,0=(3/4)x-3/2

3/4x=3/2

x=2

here the coordinating point is (2,0)

Hope This Helps.

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