Question : The factors of $x^2+4 y^2+4 y-4 x y-2 x-8$ are:
Option 1: $(x-2 y-4)(x-2 y+2)$
Option 2: $\left(x^2-2 y-4\right)\left(x^2-2 y+2\right)$
Option 3: $(x+2 y-4)(x+2 y+2)$
Option 4: $\left(x^2-2 y-4\right)\left(x^2+2 y+2\right)$
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: $(x-2 y-4)(x-2 y+2)$
Solution : $x^2+4 y^2+4 y-4 x y-2 x-8$ = $(x^2+(2y)^2-2(2xy))-2(x-2y)-8$ = $(x-2y)^2-2(x-2y)-8)$ = $(x-2y)^2-4(x-2y)+2(x-2y)-8)$ = $(x-2y+2)(x-2y-4)$ Hence, the correct answer is $(x-2y+2)(x-2y-4)$.
Candidates can download this ebook to know all about SSC CGL.
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Question : The factors of $ x^4+x^2+25$ are:
Question : The simplified value of $\small \left (1-\frac{2xy}{x^{2}+y^{2}}\right )\div\left (\frac{x^{3}-y^{3}}{x-y}-3xy\right)$ is:
Question : If $(x+y)^3+8(x-y)^3=(3 x+A y)\left(3 x^2+B x y+C y^2\right)$, then the value of (A + B + C) is:
Question : What is the LCM of $\left(8 x^3+80 x^2+200 x\right)$ and $\left(4 x^4+16 x^3-20 x^2\right)$?
Question : The third proportional to $\left(x^2-y^2\right)$ and $(x-y)$ is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile