Question : The following table shows the percentage of the population of five states below the poverty line and the proportion of males and females below and above the poverty line.
State | Percentage of the Population Below the Poverty Line | Proportion of Males and Females | |
Below Poverty Line | Above Poverty Line | ||
Males: Females | Males: Females | ||
A | 25% | 7 : 3 | 1 : 5 |
B | 13% | 8 : 5 | 1 : 7 |
C | 26% | 9 : 4 | 2 : 11 |
D | 11% | 4 : 3 | 13 : 4 |
E | 17% | 5 : 9 | 3 : 2 |
If the population of State B and State C is 6,000 each, then what is the total number of females below the poverty line in these two states?
Option 1: 720
Option 2: 780
Option 3: 740
Option 4: 750
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Correct Answer: 780
Solution :
Population of State B = 6000
Percentage of people below the poverty line in State B = 13%
Number of people below the poverty line in State B = 13% of 6000 = 780
The ratio of males to females in State B below the poverty line = 8 : 5
Number of females below poverty line in State B = $\frac{5}{5+8}\times 780=300$
Population of State C = 6000
Percentage of people below the poverty line in State C = 26%
Number of people below the poverty line in State C = 26% of 6000 = 1560
The ratio of males to females in State C below the poverty line = 9 : 4
Number of females below poverty line in State C = $\frac{4}{4+9}\times 1560=480$
Total number of females below the poverty line in States B and C = 300 + 480 = 780
Hence, the correct answer is 780.