Question : The greatest fraction among $\frac{2}{3}, \frac{5}{6}, \frac{11}{15} and \frac{7}{8} is:$
Option 1: $\frac{7}{8}$
Option 2: $\frac{11}{15}$
Option 3: $\frac{5}{6}$
Option 4: $\frac{2}{3}$

Question

Question : Solve the following.
$\frac{24 \div \frac{3}{8} of (8 + 2 \times \overset{―}{7 - 3}) + [\frac{2}{11} \div \frac{4}{55} - {\frac{5}{8} + \frac{6}{16}}]}{32 \div \overset{―}{15 - 7} + 75 \div (6 + 15 \div 3 + 4)}$
Option 1: $\frac{23}{27}$
Option 2: $\frac{9}{2}$
Option 3: $\frac{11}{18}$
Option 4: $\frac{15}{19}$

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Answer 1

Correct Answer: $\frac{7}{8}$

Solution : Given numbers are = $\frac{2}{3}, \frac{5}{6}, \frac{11}{15}, \frac{7}{8}$
LCM of denominators (3, 6, 15, 8) = $3 \times 2 \times 5 \times 4 = 120$
Making all denominators the same for comparison,
$\Rightarrow \frac{2}{3} \times \frac{40}{40} = \frac{80}{120}$
$\Rightarrow \frac{5}{6} \times \frac{20}{20} = \frac{100}{120}$
$\Rightarrow \frac{11}{15} \times \frac{8}{8} = \frac{88}{120}$
$\Rightarrow \frac{7}{8} \times \frac{15}{15} = \frac{105}{120}$
Now, compare the numerators (105 > 100 > 88 > 80)
So, $\frac{7}{8}$ is the greatest fraction.
Hence, the correct answer is $\frac{7}{8}$ .

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Question : The greatest fraction among 23,56,1115 and 78 is:Option 1: 78Option 2: 1115Option 3: 56Option 4: 23

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Question : The greatest fraction among $\frac{2}{3}, \frac{5}{6}, \frac{11}{15} and \frac{7}{8} is:$
Option 1: $\frac{7}{8}$
Option 2: $\frac{11}{15}$
Option 3: $\frac{5}{6}$
Option 4: $\frac{2}{3}$